(7x+3)(4x^2-19x-5)=0

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Solution for (7x+3)(4x^2-19x-5)=0 equation: 


Simplifying
(7x + 3)(4x2 + -19x + -5) = 0

Reorder the terms:
(3 + 7x)(4x2 + -19x + -5) = 0

Reorder the terms:
(3 + 7x)(-5 + -19x + 4x2) = 0

Multiply (3 + 7x) * (-5 + -19x + 4x2)
(3(-5 + -19x + 4x2) + 7x * (-5 + -19x + 4x2)) = 0
((-5 * 3 + -19x * 3 + 4x2 * 3) + 7x * (-5 + -19x + 4x2)) = 0
((-15 + -57x + 12x2) + 7x * (-5 + -19x + 4x2)) = 0
(-15 + -57x + 12x2 + (-5 * 7x + -19x * 7x + 4x2 * 7x)) = 0
(-15 + -57x + 12x2 + (-35x + -133x2 + 28x3)) = 0

Reorder the terms:
(-15 + -57x + -35x + 12x2 + -133x2 + 28x3) = 0

Combine like terms: -57x + -35x = -92x
(-15 + -92x + 12x2 + -133x2 + 28x3) = 0

Combine like terms: 12x2 + -133x2 = -121x2
(-15 + -92x + -121x2 + 28x3) = 0

Solving
-15 + -92x + -121x2 + 28x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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